Luas diagonal bidangnya adalah...
Penyelesaian soal :
- Diagonal Sisi
[tex] \sf s \sqrt{2} [/tex]
[tex] \sf = 6 \sqrt{2} [/tex]
[tex] \\ [/tex]
- Luas Bidang Diagonal
[tex] \sf = 6 \times 6 \sqrt{2} [/tex]
[tex] \sf = 36 \sqrt{2} [/tex]
[tex] \\ [/tex]
Tysm!
Jawaban:
Diagonal sisi
s√2
= 16√2
Luas Diagonal Bidang
= ( 6 × 6 )√2
= 36√2
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